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Write the sum of 7√28x6+4√7x6 in simplest form, if x≠0

Write the sum of 7√28x6+4√7x6 in simplest form, if x≠0-example-1
User Brian Stork
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2 Answers

26 votes
26 votes

Answer:

0

Explanation:

7√2(8)(06)+4√7(06)

7√2(8)(06)+4√7(06)

=0

User PSK
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27 votes
27 votes

The simplified form of
\(7√(28x^6) + 4√(7x^6)\) is
\(x(14 + 4x)\).

To simplify the expression
\(7√(28x^6) + 4√(7x^6)\), you can first factor out any common factors from the radicands (the expressions inside the square roots).

Step 1: Factor out common factors from the radicands.


\(7√(28x^6)\) can be simplified as follows:


\(7√(28x^6) = 7√((4x^2)(7x^4))\)

Similarly, for
\(4√(7x^6)\), you can factor out the common factors:


\(4√(7x^6) = 4√((1x^2)(7x^4))\)

Step 2: Simplify the square roots of the factored expressions.

Now, let's simplify each square root individually:

For
\(7√((4x^2)(7x^4))\), you can split it into two square roots:


\(7√((4x^2)(7x^4)) = 7√(4x^2) \cdot √(7x^4)\)

Simplify each square root separately:


\(7√(4x^2) = 7(2x) = 14x\)


\(√(7x^4) = x^2\)

Similarly, for
\(4√((1x^2)(7x^4))\), you can split it into two square roots:


\(4√((1x^2)(7x^4)) = 4√(x^2) \cdot √(7x^4)\)

Simplify each square root separately:


\(4√(x^2) = 4x\)


\(√(7x^4) = x^2\)

Step 3: Combine the simplified square roots.

Now that both square roots have been simplified, combine them back into a single expression:


\(14x + 4x^2\)

Step 4: Factor out the common factor, which is x:


\(x(14 + 4x)\)

So, the answer is
\(x(14 + 4x)\).

User Avianey
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2.8k points