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21 votes
21 votes
Hey can anyone please help me with this it’s due in few hours and I’m stuck

Hey can anyone please help me with this it’s due in few hours and I’m stuck-example-1
User Luis Morales
by
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1 Answer

13 votes
13 votes

Answer:

1) P = rho g h = d g h where d is replacing the greek letter rho (density)

a) pressure at A must be 1/2 that of B because of 1/2 the height

b) pressure at B equals that at D because the height is the same

(Pascal's principle - pressure in a fluid is same in all directions)

c) pressure A is the same as that C

d) the pressure at B would be .8 of the water at B if paraffin replaced the water (P = d g h = .8 * dw g h) due to change in density

2) Volume = 4 m X 3 m X 2 m) = 24 m^3 volume of tank

b) mass = volume * density = 24 m^3 * 800 kg / m^3 = 19,200 kg

c) weight = mass * gravity = 19,200 kg * 9.8 m/s^2 = 188,160 Newton's

d) P = d g h = 800 kg/m^3 * 9.8 m/s^2 * 2 m 15,680 N/m^2

Pressure is given in force/area or N/m^2

3) Pw / Pp = dw / dp = 1000 / 800 = 1.25

Pw = 1.25 Pp = 15,680 m/s^2 * 1.25 = 19,600 Pascal's