Question

Find the distance from point A(15,−21) to the line 5x+2y = 4 . Round your answer to the nearest tenth.

Answer 1

5.4 units

Explanation:

5x + 2y - 4 = 0 and (15, - 21)

d = |(A*Px)+(B*Py)+C| / (sqrt A^ + B^2)

A=5, B=2, C= - 4 and Px=15, Py= -21

d =|(5*15)+(2*-21)+ -4| / (5^2 + 2^2)

= |75-42-4| / sqrt 29

= 29/sqrt 29 = 5.4