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10 votes
10 votes
Alice is deciding where to go on her next trip. She is reviewing some information packets. She has packets advertising European trips numbered 1,2,3, packets advertising African trips numbered 1,2,3,4,5,6, and packets advertising South American trips numbered 1,2. If a single packet is picked at random, what is the probability that the packet is advertising a South American trip AND has an odd number?

Provide the final answer as a fraction.

User SolomonT
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2 Answers

26 votes
26 votes

Answer:

1/11

Explanation:

User Wannes Rosiers
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23 votes
23 votes

Answer:

1/11

There are a total of 3+6+2=11 packets. Of these, there is 1 card that is advertising a South American trip and has an odd number, so the answer is 1/11.

Explanation:

User D Whelan
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2.9k points