Question

Help for questions 13, and 15

Answer 1

Below

Step-by-step explanation:

13. Given : Vx = 61.5 m/s , dx = 291 m , dy = ?

First we need to find the time of flight for this projectile :

dx = vx (t)

291 = 61.5(t)

4.7317 s = t

Now we can find dy with this equation :

`dy = (t^2(g))/(2)`

`dy = (4.7317^2(9.8))/(2)`

`dy = 109.706`

We need to round this to 3 sig figs :

`dy = 110 m`

15. I just realized I already solved for that above! It is 4.73 seconds!

Hope this helps! Best of luck <3