Answer:
first multiply 3 with −8 and we get − 24
then find two numbers that if we add or subtract we get + 10 and if we multiply we get − 24
and the numbers are + 12 and −2
then we place those numbers as follow :-
3x²+12x−2x−8
then we group them
(3x2+12x)(−2x−8)
now take the common factor out.
3x(x+4)−2(x+4)
then group the numbers outside of the brackets
(3x−2)(x+4)
And that is the answer:
Proper Solution:-
1.) 3x2+10x−8
2.) 3x2+12x−2x−8
3.) (3x2+12x)(−2x−8)
4.) 3x(x+4)−2(x+4)
5.) (3x−2)(x+4)