Question

I know the answer, I just don't know how my teacher got it. Can anyone teach me how to solve it please.

How many moles of oxygen are present in 0.798 moles of Mg(IO3)2?
Answer: 4.79 mol

Answer 1

About 4.79 moles of oxygen.

Step-by-step explanation:

We want to determine the amount of moles of oxygen are present in 0.798 moles of Mg(IO₃)₂.

From the chemical formula, we can see that there are six atoms of oxygen for every molecule of Mg(IO₃)₂. Therefore, we can say that there are six moles of oxygen for every mole of Mg(IO₃)₂. This yields the following ratio:

`\displaystyle \frac{6\text{ mol O}}{1 \text{ mol Mg(IO$_3$)$_2$}}`

Multiplying this by the initial value yields:

`\displaystyle 0.798 \text{ mol Mg(IO$_3$)$_2$} \cdot \displaystyle \frac{6\text{ mol O}}{1 \text{ mol Mg(IO$_3$)$_2$}} = 4.79 \text{ mol O}`

In conclusion, there are about 4.79 moles of oxygen present in 0.798 moles of Mg(IO₃)₂.