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In ∆OPQ, q =18cm, o=96cm and



User Mtleis
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1 Answer

4 votes

Given the information on the problem, we can use the law of cosines to find the length of p with the following equation:


p^2=q^2+o^2-2q\cdot o\cdot\cos P

substituting the values at hand, we get the following:


\begin{gathered} p^2=(18)^2+(96)^2-2(18)(96)\cos 142 \\ \Rightarrow p^2=324+9216+2723.37 \\ \Rightarrow p^2=12263.37 \\ \Rightarrow p=\sqrt[]{12263.37}=110.74 \\ p=110.7\operatorname{cm} \end{gathered}

therefore, the length of p is 111 cm

User Ekansh Rastogi
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