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What quantity in moles of phosphorus atoms do you have if you have 2.40 × 10²² atoms of phosphorus. (The mass of one mole of phosphorus is 30.97 g.)

1 Answer

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Answer:

0.04 mole or 1.23 g

Step-by-step explanation:

1 mole of P has 6.02 x 10^23 atoms

so quantity in moles of P of 2.40 x 10^22 atoms equal

1 mole x (2.40 x 10^22)/(6.02 x 10^23)

= 0.03986710963 or 0.04 mole

1 mole of P = 6.02 x 10^23 atoms = 30.97 g

2.40 x 10^22 atoms weights

(30.97)(2.40 x 10^22)/(6.02 x 10^23)

= 1.23468438538 or 1.23 g

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