Final answer:
XeF4 does not have a resonance structure because its Lewis structure, which has an octahedral electron-pair geometry and a square planar molecular structure, does not contain alternating single and double bonds to allow for resonance.
Step-by-step explanation:
Does XeF4 have a resonance structure? The answer is no, XeF4 does not exhibit resonance. The Lewis structure of XeF4 shows that there are six regions of high electron density around the xenon atom: four being the bonds with fluorine atoms and two are lone pairs. According to VSEPR theory, the electron-pair geometry of XeF4 is octahedral, with the lone pairs forming a linear geometry opposite one another, resulting in a molecular structure that is square planar. This arrangement is symmetrical and does not allow for resonance because there are no alternating single and double bonds, which are characteristic of molecules that exhibit resonance.