Question

6. Find the equation for a parabola with vertex (5,-8) containing the point (1,1).

Answer 1

`y=(9)/(16)(x-5)^2-8`

Explanation:

The equation in vertex form is
`y=a(x-5)^2-8`.

Substituting in the coordinates
`(1,1)` to solve for
`a`,

`1=a(1-5)^2-8 \\ \\ 1=16a-8 \\ \\ 9=16a \\ \\ a=9/16`

So, the equation is
`y=(9)/(16)(x-5)^2-8`.