1 Answer

JeremyE · Answer 1 · 2023-06-30T10:09:02+0000

Answer:

${ \tt{ {x}^(2) + 2 = 0 }} \\ \\ { \tt{ {x}^(2) = - 2 }} \\ \\ { \tt{x = √( - 2) }}$

- At this point, we can't operate the square root. Let's introduce the imaginary part of a value

From complex numbers;

${ \boxed{ \tt{{ \red{note} \: {\rightarrow{i * i = - 1 = {i}^(2) }}}}}}$

Therefore;

${ \tt{x = \sqrt{2 * {i}^(2) } }} \\ \\ { \boxed{ \rm{ \: x = i √(2) \: \: }}}$

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