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How many moles of Oz would be required to generate 13.0 mol of NO2 in the reaction below assuming the reaction has only 74.1% yield? 2 NO (g) + O2 (g) → 2 NO2 (g)
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10 votes
10 votes
How many moles of Oz would be required to generate 13.0 mol of NO2

in the reaction below assuming the reaction has only 74.1% yield?
2 NO (g) + O2 (g) → 2 NO2 (g)

User Davidsun
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1 Answer

14 votes
14 votes

Answer:32

Step-by-step explanation:

Have a nice day :)

User Vivatus
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