Question

Write an equation of the line passing through point P(2, 3) that is perpendicular to the line y-4=-2(x+3) .

Answer 1

`\\ \sf\longmapsto y-4=-2(x+3)`

Here slope is -2

• The perpendicular line have additive and multiplicative inverse slope

m=1/2

Put co-ordinates of P in equation

`\\ \sf\longmapsto y-3=(1)/(2)(x+2)`

Answer 2

• y - 3 = 1/2(x - 2)

Explanation:

The given line has a slope of -2.

The perpendicular line will have a negative-reciprocal slope:

• m = 1/2

Use same point-slope form and the point P(2, 3):

• y - y₁ = m(x - x₁)
• y - 3 = 1/2(x - 2)