If you throw a rock up into the air as hard as you can and it stays in the air a total of 6.0 s, the velocity of the rock when you threw it would be 30 m/s².
What was the velocity?
The velocity of the rock when it was thrown can be obtained by noting the acceleration, and the total time spent while applying this in the formula v = at/2
So, we have the acceleration as 0 m/s²
time spent is = 6 secs
the velocity is unknown
10 m/s * 6/2
= 30 m/s
So, if you throw a rock up into the air as hard as you can and it stays in the air for a total of 6.0 seconds, the velocity of the rock when you threw it would be 30 m/s.