Answer:
see explanation
Explanation:
(a)
given the arithmetic series 5 + a + 14 + b
the difference between consecutive terms is constant , that is
a₂ - a₂ = a₃ - a₂ ( substitute values )
a - 5 = 14 - a ( add a to both sides )
2a - 5 = 14 ( add 5 to both sides )
2a = 19 ( divide both sides by 2 )
a = 9.5
then
a₄ - a₃ = a₂ - a₁
b - 14 = a - 5 = 9.5 - 5 = 4.5 ( add 14 to both sides )
b = 18.5
(b)
the sum to n terms of an arithmetic series is
=
[ 2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
here a₁ = 5 and d = a₂ - a₁ = 14 - a = 14 - 9.5 = 4.5 , then
S₁₀ =
[ (2 × 5) + (9 × 4.5) ]
= 5(10 + 40.5)
= 5 × 50.5
= 252.5
(c)
> 500 , that is
(50.5) > 500 ( multiply both sides by 2 )
50.5n > 1000 ( divide both sides by 50.5 )
n > 19.80198... , that is
n = 20