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3x+15>12 solve for inequality

User Julumme
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1 Answer

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Hi :)

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#1 Subtract by 15 both sides


\frak{3\rm{x}\frak{+15\textgreater12}}


\frak{3}\rm{x}\frak{\textgreater{12-15}}


\frak{3}\rm{x} > \frak{-3}

#2 Divide 3 into both sides


\frak{3}\rm{x}\textgreater\frak{-3}

x>-1

User Arennuit
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