Given :-
- Two cubes each of volume 27cm³ are joined to make a cuboid .
To Find :-
- The surface area of the resulting solid .
Solution :-
Given that the volume of cube is 27cm³ . We know that the volume of cube is given by (side)³ .
So , if we assume each side to be a , then ,
a³ = 27cm³
a = ³√{27cm³}
a = ³√3³cm³
a = 3 cm .
- Hence , if we join two cubes we will get a cuboid of length 3cm + 3cm = 6cm . (l)
- The breadth would be 3cm .( b)
- The height would be 3cm .(h)
See attachment for figure .
And as we know that TSA of cuboid is ,
TSA = 2( lb + bh + hl )
TSA = 2 ( 6*3 + 3*3 + 3*6) cm²
TSA = 2 ( 18 +9 +18 )cm²
TSA = 2 * 45cm²
TSA = 90 cm²
Hence the new surface area of the solid is 90cm² .
I hope this helps.