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27 votes
27 votes
What factors of 12n2- 10n+2

User Afterlame
by
3.5k points

2 Answers

13 votes
13 votes

Answer:

((22•3n2) - 10n) + 2

STEP 1 :

Equation at the end of step 1

((22•3n2) - 10n) + 2

STEP 2 :

STEP 3 :

Pulling out like terms

3.1 Pull out like factors :

12n2 - 10n + 2 = 2 • (6n2 - 5n + 1)

Trying to factor by splitting the middle term

3.2 Factoring 6n2 - 5n + 1

The first term is, 6n2 its coefficient is 6 .

The middle term is, -5n its coefficient is -5 .

The last term, "the constant", is +1

Step-1 : Multiply the coefficient of the first term by the constant 6 • 1 = 6

Step-2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is -5 .

-6 + -1 = -7

-3 + -2 = -5 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -2

6n2 - 3n - 2n - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

3n • (2n-1)

Add up the last 2 terms, pulling out common factors :

1 • (2n-1)

Step-5 : Add up the four terms of step 4 :

(3n-1) • (2n-1)

Which is the desired factorization

Final result :

2 • (2n - 1) • (3n - 1)

Explanation:

User Blackghost
by
2.8k points
11 votes
11 votes

Answer:

2(2n-1)(3n-1)

Explanation:

User Scully
by
3.1k points
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