Question

A metal ball with a constant speed of 15 m/s rolls off the edge of a table. The table is 2.7 m high. How far from the edge of the table does the ball land?

Answer 1

11.135 m

Step-by-step explanation:

First, we need to find time, recall:

`x=vt+1/2at^2`

We need to find time to ground, therefore:

`y=vyt+1/2ayt^2`

substitue values for vertical:

`2.7=1/2*9.8t^2\\2.7=4.9t^2\\√(2.7/4.9)=√(t) \\0.74230=t\\`

Now plug it in for velocity:

`15*0.74230=11.135`