Question

(0,4) and (-2,-2) what is the linear equation

Answer 1

`gradient = (change \: in \: y)/(change \: in \: x) \\ = (y2 - y1)/(x2 - x1) \\ = (4 - - 2)/(0 - - 2) \\ = (6)/(2) \\ = (3)/(1) \\ let \: (xy) \: also \: lie \: on \: the \: line \\ gradient \: = (y2 - y1)/(x2 -x1) \\ (3)/(1) = (x - - 2)/(y - - 2) \\ (3)/(1) = (x + 2)/(y + 2) \\ 3(y + 2) = 1(x + 2) \\ 3y + 6 = x + 2 \\ 3y + 6 - 2 = x \\ 3y + 4 = x`

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