Question

Suppose a basketball team had a season of games with the following characteristics:

Of all the games, 60% were at-home games. Denote this by H (the remaining were away games).
Of all the games, 25% were wins. Denote this by W (the remaining were losses).
Of all the games, 20% were at-home wins.
Of the at-home games, we are interested in finding what proportion were wins.

Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?

a. 0.05
b. 0.12
c. 0.15
d. 0.42
e. 0.80

Answer 1

correct Ans:

P(H) = 0.60

P(W | H) = P(H and W)/P(H)=

0.33

0.20/0.60

my mistake:

P(H and W) = 0.20