Question

What is the equation of a line perpendicular to y=1/4x-3 that passes through point (-2,4)?

Answer 1

Explanation:

To find a line perpendicular to one another and passing through the point we take the slope of the original line and apply its reciprocal in point slope form.

Reciprocal of
`(1)/(4)` is
`(-4)/(1)=-4`

Now plug the slope into point-slope form with the known x and y values:

`x-(-2)=-4(y-4)\\x+2=-4(y-4)\\x+2=-4y+16\\x+2+4y=16\\4y=16-x-2\\y=4-(x)/(4)-(2)/(4)\\y=3.5-(x)/(4)`