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Find a so that the point (-1,4) is on the graph of f(x)=ax^2+3
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4 votes
Find a so that the point (-1,4) is on the graph of f(x)=ax^2+3

User Alvi
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1 Answer

4 votes
f(x)=ax^2+3
4=a(-1^2)+3
4=a(1)+3
a=4-3
a=1

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User Jkazan
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