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A part of an mRNA molecule with the following sequence is being read by a ribosome: 5'-GGC-UGC-3' (mRNA). The charged transfer RNA molecules shown in the figure below (with their anticodons shown in the 3' to 5' direction) are available. Two of them can correctly match the mRNA so that a dipeptide can form:

tRNA Anticodon Amino Acid
GGC
Proline
CGU
Alanine
UGC
Threonine
CCG
Glycine
ACG
Cysteine
CGG
Alanine

Which of the following dipeptides will be formed?
Proline-Threonine
Glycine-Cysteine
Alanine-Alanine
Cysteine-Alanine

User Jinx
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2 Answers

15 votes
15 votes

Final answer:

The dipeptide formed from the mRNA sequence 5'-GGC-UGC-3' is Glycine-Cysteine, matching the anticodons CCG (Glycine) and ACG (Cysteine) to the mRNA codons.

Step-by-step explanation:

The question involves the process of translation in protein synthesis where an mRNA sequence is read by a ribosome and the corresponding amino acids are linked to form a dipeptide. The mRNA sequence 5'-GGC-UGC-3' will be translated into a dipeptide using the available tRNAs listed. To determine which tRNAs will bind to this mRNA, we must match the anticodon of the tRNA with the codon of the mRNA, ensuring the proper base pairing (G pairs with C and A pairs with U).

The first codon in the mRNA sequence is GGC, so we need a tRNA with an anticodon that is complementary to GGC. The tRNA with the anticodon CCG (which carries glycine) is the correct match for this codon. The second codon in the mRNA sequence is UGC. The appropriate tRNA for this codon is the one with the anticodon ACG (which carries cysteine).

Therefore, the correct dipeptide formed will be Glycine-Cysteine as the ribosome reads the mRNA from 5' to 3' end.

User Rik Heywood
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2.9k points
17 votes
17 votes

Answer:Proline

Step-by-step explanation:

User Otto
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3.1k points
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