Please someone help me Balance this equation. K2CrO7 + H2SO4 + 2C2H5OH = 3CH3COOH + 2K2SO4 + 4H2O + 2Cr2(SO4)3.

Gabcvit asked Mar 7, 2022

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Please someone help me Balance this equation.

K2CrO7 + H2SO4 + 2C2H5OH = 3CH3COOH + 2K2SO4 + 4H2O + 2Cr2(SO4)3.

Gabcvit asked Mar 7, 2022

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11 votes

Answer: This is an oxidation-reduction (redox) reaction:

3 C-II - 12 e- → 3 CII (oxidation)

4 CrVI + 12 e- → 4 CrIII (reduction)

C2H5OH is a reducing agent, K2Cr2O7 is an oxidizing agent.

CAmador answered Mar 12, 2022

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