148k views
2 votes
Drag each length to the correct location on the image. Each length can be used more than once, but not all lengths will be used.

What are the missing segment lengths in the image?
12√3
24
12√2
12
45
E
45°
12
24√3 24√2
45°
45°

Drag each length to the correct location on the image. Each length can be used more-example-1
User Fang Zhang
by
5.9k points

1 Answer

2 votes

Answer:

DF=12√2

FG=12√2

DG=24

Explanation:

Ratio of special Right Triangle (45:45:90): x:x:x√2

Triangle DEF: x:x:x√2

x=12

12: 12: 12√2

So, DF= 12√2

Opposite (if q, then p) Base angle theorem. So, FD≅FG.

FD=12√2

FG=12√2

Ratio of 45:45:90 Triangle: x:x::x√2

x in triangle FDG= 12√2

12√2:12√2:12√2(√2)

12√2*√2=24

=12√2: 12√2: 24

DG=24

User Enigma Plus
by
5.5k points