Please help me it is algebra and I need it evaluated

asked Dec 20, 2023 58.8k views

1 vote

5.1k points

Please log in or register to add a comment.

4 votes

Answer:

Explanation:

Log 64 base 4

64=
4^(X)

$4^(3) =4^(X) \\\\The base cancels out\\3= X$

22)

$Log 16 base 4 = x\\\\16=4^(x) \\4^(2) =4^(x) \\$

The base will cancel out

2=x

30) Log 1/216 base 6

$(1)/(216) = 6^(x) \\\216^(-1) =6^(x) \\6^((3)(-1)) =6^(x) \\6^(-3) =6^(x)$

The base will cancel out

x=-3

5.1k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.6m questions

7.3m answers