Question

Please help!!

Which number is greater?
a)The square root of 64
b) The square root of 16

Answer 1

Neither, they are both equal.

Explanation:

FYI, that three in front of the radical in the first expression is actually cube root. The cube root of 64 is 4, and the square root of 16 is 4.

`\sqrt[3]{64} =4\\√(16)=4\\4=4`

Answer 2

`\huge\text{Hey there!}`

`\huge\textsf{Option A }\huge\boxed {\downarrow}`

`\huge\boxed{\rm{\sqrt[3]{64}}}}\\\huge\boxed{= \rm{\sqrt[3]{4^3}}}}\\\huge\boxed{= \rm{\sqrt[3]{4*4 *4}}}\\\huge\boxed{\rm{\rightarrow √(64)= 8, \ because \ 8*8 = \bf 64}}\\\huge\boxed{\rm{{= (8)/(2)\rightarrow 8/ 2 \rightarrow \bf 4}}}`

`\huge\boxed{\textsf{Option A.) answer: \bf 4}}`

`\huge\textsf{Possible Option A. part II }\huge\boxed\downarrow`

`\huge\boxed{\rm{√(64) = √(8*8)= \bf 8}}\\\huge\boxed{\text{Possible answer for Option A. part II: \bf 8}}`

`\huge\textsf{Option B }\huge\boxed\downarrow`

`\huge\boxed{\rm{√(16)}}\\\huge\boxed{\rm{= √(4*4)}}\\\huge\boxed{\rm{= √(16) \rightarrow \bold{4}\rightarrow 4*4 \rightarrow \bf 16}}`

`\huge\boxed{\textsf{Option B.) answer: \bf 4}}`

~
`\frak{Amphitrite1040:)}`