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Find 5 consecutive even integers such that the largest is 12 less than twice the smallest.
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5 votes
5 votes
Find 5 consecutive even integers such that

the largest is 12 less than twice the
smallest.

User Gionata
by
2.5k points

2 Answers

25 votes
25 votes

Answer:

10,8,6,4,2,

Explanation:

it is all even

User Thomas Stock
by
2.7k points
8 votes
8 votes
x, x+2, x+4, x+6, x+8
Largest: x+8
Smallest: x
x+8 = 2x - 12
12+8 = x
x=20
Numbers: 20, 22, 24, 26, 28
User Bseaborn
by
2.7k points
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