Question

14(5+8)

In Step 1, Angelica applied the distributive property. She multiplied 14 by each of the addends inside the parentheses. Which expression demonstrates Angelica multiplying 14 by each addend?
(14⋅5)+(5⋅8)
(14⋅5)+(14⋅8)
5+(14⋅8)
(14⋅5)+8

Answer 1

Answer:Expand the equation.

Multiply (distribute) the first numbers of each set, outer numbers of each set, inner numbers of each set, and the last numbers of each set.

Combine like terms.

Solve the equation and simplify, if needed.

Explanation:

Answer 2

The second option :)