Question

What is the 6th term in the sequence below?
4,-8, 16, -32,

Answer 1

−128

Explanation:

Answer 2

Assuming the pattern continues...

Answer:

`128`

Explanation:

We see that this is a geometric series with common ratio
`-2`.

So, the 6th term is the 4th term times
`(-2)^2=2^2=4`.

So, the answer is
`4(-32)=\boxed{128}` and we're done!

Note:

The closed form for this geometric series is
`4*(-2)^(n-1)`, which means the nth term is always
`4*(-2)^(n-1)`.