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What are the solutions to this polynominal when s(x)=0? S(X)= (3x^2+17x +10)(x-7)(4x-3)

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Answer:

-5, -2/3, 7, 3/4

Explanation:

The solutions of S(x) = 0 satisfy one of the equations:

3x^2 + 17x + 10 = 0, x - 7 = 0, 4x - 3 = 0

The latter two are straightforward to solve:

x = 7 and x = 3/4

We now factor 3x^2 + 17x + 10 = 0

Note 10 = 5 * 2, 3 = 3 * 1 and 3 * 5 + 2 - 17.

So, we can factor it as (3x + 2) (x + 5) = 0

Thus, we also have solutions -2/3, -5.

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