Answer:
y = -
![(√(111) )/(20)](https://img.qammunity.org/2023/formulas/mathematics/college/isyicvf6x9r08rbml3yr9miuxnja9nodle.png)
Explanation:
using Pythagoras' identity in the right triangle formed by the radius 1 and the given point, then
y² + (-
)² = 1²
y² +
= 1
y² = 1 -
=
( take square root of both sides )
y = ±
= ±
![(√(111) )/(20)](https://img.qammunity.org/2023/formulas/mathematics/college/isyicvf6x9r08rbml3yr9miuxnja9nodle.png)
since the point is in the third quadrant then y < 0
y = -
![(√(111) )/(20)](https://img.qammunity.org/2023/formulas/mathematics/college/isyicvf6x9r08rbml3yr9miuxnja9nodle.png)