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The last of my points. Given the unit circle, what is the value of y? This my last question.

The last of my points. Given the unit circle, what is the value of y? This my last-example-1
User Gladman
by
3.1k points

1 Answer

1 vote

Answer:

y = -
(√(111) )/(20)

Explanation:

using Pythagoras' identity in the right triangle formed by the radius 1 and the given point, then

y² + (-
(17)/(20) )² = 1²

y² +
(289)/(400) = 1

y² = 1 -
(289)/(400) =
(111)/(400) ( take square root of both sides )

y = ±
\sqrt{(111)/(400) } = ±
(√(111) )/(20)

since the point is in the third quadrant then y < 0

y = -
(√(111) )/(20)

User Brooks DuBois
by
3.3k points