Question

What are the solutions of x² + 6x - 16 = 0?

Answer 1

Explanation:

`x_(1,\:2)=(-6\pm √(6^2-4\cdot \:1\cdot \left(-16\right)))/(2\cdot \:1)\\√(6^2-4\cdot \:1\cdot \left(-16\right))\\√(6^2+64)\\√(36+64)\\√(100)\\√(10^2)\\=10\\x_1=(-6+10)/(2\cdot \:1),\:x_2=(-6-10)/(2\cdot \:1)\\\\\bold{x_1:2}\\(-6+10)/(2\cdot \:1)\\(4)/(2\cdot \:1)\\(4)/(2)\\=2\\\\\bold{x_2:-8}\\(-6-10)/(2\cdot \:1)\\(-16)/(2\cdot \:1)\\(-16)/(2)\\-(16)/(2)\\=-8`

Answer:

x₁ = 2

x₂ = -8