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A 60-kg woman with a density of 980 kg/m^3 stands on a bathroom scale. Determine the reduction of the scale reading due to air. (The answer is 0.774 N)
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A 60-kg woman with a density of 980 kg/m^3 stands on a bathroom scale. Determine the reduction of the scale reading due to air. (The answer is 0.774 N)

User Inbal
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Answer:

The woman displaces a volume of air equivalent to her own volume; VV; V=\dfrac{m}{\rho_{\text{woman}}}=\dfrac{60}{980}=0.0612\mathrm{\ m^3}V= ρ woman m = 98060 =0.0612 m 3

Step-by-step explanation:

User Zack Allen
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