Question

Write the equation of a Quadratic Function that has its vertex at (-3, 2) and goes through the point (-1, -2).​

Answer 1

`y = a {(x - b)}^(2) + c \\ vertrix \: \binom{b}{c} = \binom{ - 3}{2} \\ point \: \binom{ - 1}{ - 2} \\ - 2 = a {(( - 1) - ( - 3))}^(2) + 2 \\ - 4 = a4 \\ \therefore \: a = - 1 \\ y = - {(x + 3)}^(2) + 2 \\y = - {x}^(2) - 6x - 9 + 2 \\ y = - {x}^(2) - 6x - 7`