Question

In a mixture of 3 gases what is the total pressure of the gases if Gas A exerts a pressure

of 400 mmHg, Gas B exerts a pressure of 220 mmHg and Gas C exerts a pressure of 140
mm Hg?

Answer 1

760 mm of Hg

Step-by-step explanation:

If the gases A , B and C are non reacting , then according to Dalton's Law of Partial Pressure the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

`P_(total)= P_1+P_2+P_3+\dots +P_n`

Here ,

• Partial pressure of Gas A = 400mm of Hg
• Partial pressure of Gas B = 220 mm of Hg
• Partial pressure of Gas C = 140mm of Hg

Hence the total pressure exerted is ,

`P_(total)= P_(Gas\ A )+P_(Gas\ B )+P_(Gas\ C )`

Substitute ,

`P_(total)=( 400 + 220 + 140 )mm\ of \ Hg`

Add ,

`P_(total)= 760\ mm\ of \ Hg`

Hence the total pressure exerted by the gases is 760 mm of Hg.

I hope this helps.