Question

The ball takes 1.2 s to travel from player A to player B.

(i) Calculate the average speed of the ball between A and B.
If you answer this ill Call you The smartest person :)

Answer 1

Assuming one dimension & no gravity, friction, etc:
• Speed = distance/time
* A = (x1)
• B= (x2)
• Time = 1.2 sec
(|x1 - x2|)/1.2

Assuming two dimensions & no gravity, friction, etc:
• Speed = distance/time
* A = (x1, y1)
• B= (x2, y2)
• Time = 1.2 sec
(|x1 - x2| + |y1 - y2|)/1.2

Assuming 3 dimensions & no gravity, friction, etc.:
* Speed = distance/time
* A = (x1, y1, z1)
* B = (x2, y2, z2)
* Time = 1.2 sec
(|x1 - x2| + |y1 - y2| + |z1 - z2|)/1.2

Answer 2

Let distance between player A and B be x

from,

v = u + at

but,

v = u - gt, for the ball to be acted upon by gravity.

and the negative is to show the direction of g which is down.

u = initial speed(avg speed)

v will be 0m/s since it'll rest after reaching player B.

then,

0= u - (9.8*1.2)

0 =u - 11.76 m/s

u = 11.76 m/s

Therefore, the avg speed is 11.76m/s