Question

If you have a 1.45-mol sample of iron, how many moles of Fe2O3 will there be after the iron has

rusted completely?

Answer 1

3/4 of a mol of Rust

Step-by-step explanation:

The first thing you have to do is work from a balanced equation.

4Fe + 3O2 ====> 2Fe2O3

Left

4 Fe

6 Oxygens

Right

4Fe

2*3 = 6 Oxygens

So you have a balanced equation

4Fe + 3O2 ====> 2Fe2O3

1.5 x

The next (and last) thing to do is to set up a proportion

4/1.5 = 2/x Cross multiply

4x = 1.5*2 Combine

4x = 3 Divide by 4

4x/4 = 3/4

x = 3/4 mol