Question

Find the smallest positive integer that has a remainder of 2 when divided by 4 and remainder of 3 when divided

by 5.

Answer 1

18

Explanation:

Hello

The number is more by three than a multiple of of 5 (i.e 5x +3) and more than 2 than a multiple of 4 (ie 4y+2(

Now 5x+3=4y+2

ie 5x +1 =4y

we need to give the lowest pair of values to x and y such that the last equality is satisfied.

By trial, x = 3 and y = 4

thus the number is 5x+3 =5(3)+3 =18=4y+2 =4(4)+2=18

I hope it has helped you.