Question

28). A block weighs 90N and 80N respectively in air and in water. What will be the weight of the block in a brine of density 1.2g/cm?​

Answer 1

Buoyant force = g M / V * V = g d V where d is the mass / volume (density)

Fw = g * Vw * dw buoyant force of water on block (10 N)

Fbr = g * Vw * dbr buoyant force of brine on block

Fbr / Fw = 1.2 buoyant force of brine is 1.2 times that of water

Buoyant force of brine = 10 * 1.2 N = 12 N

Thus, the block will weight 90 - 12 = 78 N submersed in brine