Question

In figure , ABllEF, angle ABC=


`{70}^(0)`
and angle EFD =

`{40}^(0)`
then find x
​

Answer 1

x = 110°

Explanation:

It is given that,

→ AB || EF

→ <ABC = <CEF

→ <CEF = <DEF

Then the value of <DEF will be,

→ <DEF = 70°

Now according to Exterior angle property of a triangle the value of x will be,

→ x = <DEF + <EFD

→ x = 70 + 40

→ [ x = 110° ]

Hence, the value of x is 110°.

Answer 2

x = 110°

Given:

AB||EF means the sides are parallel and the angle is same in both.

• 
  `\triangle ABC = \triangle FED`

Find the missing angle inside the triangle:

= 180° - (40° + 70°)

= 180° - 110°

= 70°

Now the missing angle and x sum ups to 180° on a straight line:

• x + 70° = 180°

• x = 180° - 70°

• x = 110°