Question

Find k so that the line through (4,−2) and (k,2) is parallel to 8x+ 11y= 22.

Answer 1

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Answer:

k = -1.5

Explanation:

The parallel line will have a new constant:

8x +11y = c = 8(4) +11(-2) = 32 -22 = 10

Then the value of k will satisfy ...

8(k) +11(2) = 10

8k = -12 . . . . . . . . subtract 22

k = -12/8 = -1..5 . . . . . divide by 8

The parallel line will pass through (-1.5, 2). That is, k = -1.5.