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Find the length of m

Anybody can help please?

Find the length of m Anybody can help please?-example-1
User Umutesen
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1 Answer

23 votes
23 votes

Answer:

m = 10

Explanation:

We are going to use sine ratio as sine ratio is opposite to hypotenuse.

We know the value of opposite which is 5√3

The value of hypotenuse is m which is unknown.

Therefore:-


\displaystyle \large{ \sin(60 \degree) = (5 √(3) )/(m) }

We know that sin60° is √3/2


\displaystyle \large{ ( √(3) )/(2) = (5 √(3) )/(m) }

Multiply both sides by LCM which is 2m.


\displaystyle \large{ ( √(3) )/(2) (2m)= (5 √(3) )/(m) (2m)} \\ \displaystyle \large{ √(3) m=10 √(3) }

Divid both sides by √3 to isolate m.


\displaystyle \large{ ( √(3)m )/( √(3) ) = (10 √(3) )/( √(3) ) } \\ \displaystyle \large{ m = 10}

And we're done! The value of m is 10.

Alternative Solutions

If we do not want to use sin60°, we can use cos30°.

Focus the 30°, since for 30°, 5√3 is adjacent and m is hypotenuse.

cosine ratio is adjacent to hypotenuse.

Therefore:-


\displaystyle \large{ \cos(30 \degree) = (5 √(3) )/(m) }

We know that cos30° is √3/2


\displaystyle \large{ ( √(3) )/(2) = (5 √(3) )/(m) }

Notice something? Both equations when we use sin60° and cos30° are same. This is called a co-function.

Since sin60° = cos30°, both methods work.

If we do not want to use sin60°, you can use cos30°.

User Surez
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