9514 1404 393
Answer:
see attached
Explanation:
When the vector's angle α is measured CCW from the +x axis, the vector components are ...
(x, y) = (magnitude × cos(α), magnitude × sin(α))
Here, the angles are measured in different directions from different axes, so some computation is needed to arrive at the angle from the +x axis. The various axes have angle measures of ...
- +x, 0° . . . . also East
- +y, 90° . . . also North
- -x, 180° . . . also West
- -y, 270° . . . also South
Angles measured CCW from one of these directions are added; angles measured CW from one of these directions are subtracted.
The computations for multiple vectors can be tedious, so we let a spreadsheet do them. The results are attached.
Example:
Vector D is 53° CCW from the +y axis, so is 90°+53° = 143° measured CCW from the +x axis. Its components are ...
D = (10·cos(143°), 10·sin(143°)) ≈ (-7.9864, 6.0182) . . . rounded to 4 dp