Answer:
k=12
t=8
Explanation:
two equations from the question
1 k=t+6
2 (k-4)=(t-4)×2
develop these
3. k-4=2t-8
4. 2 times first equation
2k=2t+12
subtract 4 from 3
-k-4=-20
k=16
sub back in
t=10
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