Question

How many gallons of a 22% salt solution must be

mixed with a 38% salt solution to make 20 gallons of
a 28% salt solution?

Answer 1

You will need 12.5 gallons of the 22% salt solution and 7.5 gallons of the 38% of the salt solution

Explanation:

.22x + .38(20 -x) = .28(20) I want to clear the decimal, so I will multiple through by 100

100[.22x + .38(20-x)] = [.28(20)]100

22x + 38(20-x) = 28(20) Distribute the 38

22x + 760 -38x = 560 combine the x's

-16x + 720 = 560 Subtract 720 from both sides

-16x = -200 Divide both sides by -16

x = 12.5

20 - 12.5 = 7.5