Question

Henry has a fenced yard in the shape of a rectangle with a perimeter that measures 242 feet. If the width of the yard measures 51 feet, what is the length?

_(blank)_ feet

Answer 1

Answer: Length = 70 feet

Concept:

Here, we need to know how to find the perimeter of a rectangle.

Perimeter (rectangle) = 2 (l + w)

l = length

w = width

Solve:

Given information

l = l

w = 51 feet

P = 242 feet

Given expression

P = 2 (l + w)

Substitute values into the expression

242 = 2 (l + 51)

Divide 2 on both sides

242 / 2 = 2 (l + 51) / 2

121 = l + 51

Subtract 51 on both sides

121 - 51 = l + 51 - 51

`\boxed{l=70}`

Hope this helps!! :)

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