Question

A closed cylinder is filled with CO₂ gas. The mass of CO₂ in cylinder is 4.4 g. Now express this amount of Carbon dioxide in following terms:

a) no. of moles of CO₂ molecules
b) Volume at NTP
c) No. of 'gram molecule
d) No. of CO₂ molecules
e) No. of carbon atoms
f) No. of mole of Oxygen atoms
g) No. of molecules of oxygen​

Answer 1

#a

Molar mass of CO2=44g/mol

given mass=4.4g

`\\ \sf\longmapsto No\:of\;moles=(Given\:Mass)/(Molar\;Mass)=(4.4)/(44)=0.1mol`

#b

• At NTP 1mol weigh 22.4L

0.1mol weigh:-

`\\ \sf\longmapsto 22.4(0.1)=2.24L`

#c

No of molecules=Moles×Avagradro No

`\\ \sf\longmapsto 0.1* 6.023* 10^(22)=6.023* 10^(21)molecules`

#d

• CO_2 has 3atoms

No of molecules=

`\\ \sf\longmapsto 3* 6.023* 10^(21)=18.069* 10^(21)molecules`

#e

• CO2 has 1carbon

`\\ \sf\longmapsto No\:of\:molecules=6.023* 10^(21)molecules`

#f

Lets write balanced equation

`\\ \sf\longmapsto C+O_2=CO_2`

• 1mol of Oxygen exists

#g

It has 2oxygen atoms

`\\ \sf\longmapsto No\:of\:molecules=2(6.023* 10^(21))=12.046* 10^(21)`